[HackerRank/MySQL] 8월 15일 SQL 스터디 10문제 (Lv Easy. 10개)
SQL 스터디가 프로그래머스 문제를 마무리하고 해커랭크 문제풀이를 시작했다.
근데 난 밀려서 이제 인증한다.
조금 밀렸더니 써야하는 블로그가 순식간에 불어났다.
역시 사람은 조금도 나태해지면 안된다는 걸 다시금 깨달으며....
1. Revising the Select Query I
https://www.hackerrank.com/challenges/revising-the-select-query/problem?isFullScreen=true
Revising the Select Query I | HackerRank
Query the data for all American cities with populations larger than 100,000.
www.hackerrank.com
lv. easy
문제
Query all columns for all American cities in the CITY table with populations larger than 100000. The CountryCode for America is USA.
The CITY table is described as follows:
CODE
SELECT * FROM CITY WHERE POPULATION > 100000 AND COUNTRYCODE = 'USA'
2. Revising the Select Query II
https://www.hackerrank.com/challenges/revising-the-select-query-2/problem?isFullScreen=true
Revising the Select Query II | HackerRank
Query the city names for all American cities with populations larger than 120,000.
www.hackerrank.com
lv. easy
문제
Query the NAME field for all American cities in the CITY table with populations larger than 120000. The CountryCode for America is USA.
The CITY table is described as follows:
CODE
SELECT C.NAME FROM CITY C WHERE COUNTRYCODE = 'USA' AND POPULATION > 120000;
3. Select All
https://www.hackerrank.com/challenges/select-all-sql/problem?isFullScreen=true
Select All | HackerRank
Query all columns for every row in a table.
www.hackerrank.com
lv. easy
문제
Query all columns (attributes) for every row in the CITY table.
The CITY table is described as follows:
CODE
SELECT * FROM CITY;
4. Select By ID
https://www.hackerrank.com/challenges/select-by-id/problem?isFullScreen=true
Select By ID | HackerRank
Query the details of the city with ID 1661.
www.hackerrank.com
lv. easy
문제
Query all columns for a city in CITY with the ID 1661.
The CITY table is described as follows:

CODE
SELECT * FROM CITY WHERE ID = 1661;
5. Japanese Cities' Attributes
https://www.hackerrank.com/challenges/japanese-cities-attributes/problem?isFullScreen=true
Japanese Cities' Attributes | HackerRank
Query the attributes of all the cities in Japan.
www.hackerrank.com
lv. easy
문제
Query all attributes of every Japanese city in the CITY table. The COUNTRYCODE for Japan is JPN.
The CITY table is described as follows:
CODE
SELECT * FROM CITY WHERE COUNTRYCODE = 'JPN';
6. Japanese Cities' Names
https://www.hackerrank.com/challenges/japanese-cities-name/problem?isFullScreen=true
Japanese Cities' Names | HackerRank
In this challenge, you will query a list of all the Japanese cities' names.
www.hackerrank.com
lv. easy
문제
Query the names of all the Japanese cities in the CITY table. The COUNTRYCODE for Japan is JPN.
The CITY table is described as follows:
CODE
SELECT NAME FROM CITY WHERE COUNTRYCODE = 'JPN';
7. Weather Observation Station 1
https://www.hackerrank.com/challenges/weather-observation-station-1?isFullScreen=true
Weather Observation Station 1 | HackerRank
Write a query to print the CITY and STATE for each attribute in the STATION table.
www.hackerrank.com
lv. easy
문제
Query a list of CITY and STATE from the STATION table.
The STATION table is described as follows:

where LAT_N is the northern latitude and LONG_W is the western longitude.
CODE
SELECT CITY, STATE FROM STATION;
8. Weather Observation Station 3
https://www.hackerrank.com/challenges/weather-observation-station-3?isFullScreen=true
Weather Observation Station 3 | HackerRank
Query a list of unique CITY names with even ID numbers.
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lv. easy
문제
Query a list of CITY names from STATION for cities that have an even ID number. Print the results in any order, but exclude duplicates from the answer.
The STATION table is described as follows:
where LAT_N is the northern latitude and LONG_W is the western longitude.
CODE
SELECT DISTINCT(CITY) FROM STATION WHERE MOD(ID, 2) = 0
- 짝수, 홀수 판별을 위한 MOD(ID, 2) = 0 (이건 짝수!) 나눗셈 연산.
9. Weather Observation Station 4
https://www.hackerrank.com/challenges/weather-observation-station-4?isFullScreen=true
Weather Observation Station 4 | HackerRank
Find the number of duplicate CITY names in STATION.
www.hackerrank.com
lv. easy
문제
Find the difference between the total number of CITY entries in the table and the number of distinct CITY entries in the table.
The STATION table is described as follows:
where LAT_N is the northern latitude and LONG_W is the western longitude.
For example, if there are three records in the table with CITY values 'New York', 'New York', 'Bengalaru', there are 2 different city names: 'New York' and 'Bengalaru'. The query returns 1 , because total number of records - number of unique city names = 3 - 2 = 1
CODE
SELECT COUNT(*) - COUNT(DISTINCT(CITY)) FROM STATION
10. Weather Observation Station 6
https://www.hackerrank.com/challenges/weather-observation-station-6/problem?isFullScreen=true
Weather Observation Station 6 | HackerRank
Query a list of CITY names beginning with vowels (a, e, i, o, u).
www.hackerrank.com
lv. easy
문제
Query the list of CITY names starting with vowels (i.e., a, e, i, o, or u) from STATION. Your result cannot contain duplicates.
Input Format
The STATION table is described as follows:
where LAT_N is the northern latitude and LONG_W is the western longitude.
CODE
SELECT DISTINCT(CITY) FROM STATION
WHERE CITY LIKE 'a%' or CITY LIKE 'e%' or CITY LIKE 'i%' or CITY LIKE 'o%' or CITY LIKE 'u%';
- 끝! -